Ask Question
8 February, 07:25

F (x) = 8cos (2x) on (0,2π)

+5
Answers (1)
  1. 8 February, 10:11
    0
    Step-by-step explanation:

    First put the lower limit, i. e., x=0,

    F (x) = 8cos[2 (0) ]=8cos (0) = 8 (1) = 8

    ; cos (0) = 1

    Now, put the upper limit of given interval, i. e., x = π,

    F (x) = 8cos[2 (π) ]=8cos (2π) = 8 (1) = 8

    ; cos (2π) = 1
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “F (x) = 8cos (2x) on (0,2π) ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers