Find b if:

(3x-2) (x+4) = 3x^2+bx-8

Answer: b = 10

explanation: Let's solve for y.

(

3

x

-

2

)

(

x

+

4

)

=

3

x

2

+

y

x

-

8

Step 1: Flip the equation.

3

x

2

+

x

y

-

8

=

3

x

2

+

10

x

-

8

Step 2: Add - 3x^2 to both sides.

3

x

2

+

x

y

-

8

+

-

3

x

2

=

3

x

2

+

10

x

-

8

+

-

3

x

2

x

y

-

8

=

10

x

-

8

Step 3: Add 8 to both sides.

x

y

-

8

+

8

=

10

x

-

8

+

8

x

y

=

10

x

Step 4: Divide both sides by x.

x

y

x

=

10

x

x

y

=

10

Have a great day

b = 10

Step-by-step explanation:

(3x-2) (x+4) = 3x^2+bx-8

Solve:

(3x-2) (x+4) = 3x^2+bx-8

3x - 2x - 8 = 3x^2+bx-8

b = 10