Galen sold tickets for his church's carnival for a total of $2,820. Children's tickets cost $3 each and adult tickets cost $5 each. The number of children's tickets sold was 30 more than 3 times the number of adult tickets sold. How many children's tickets and how many adult tickets did he sell?

a = 195; c = 615

Step-by-step explanation:

So, you want to start by forming your equations ...

I will use 'c' for children and 'a' for adults for my variables

3a + 30 = c

(this is because of the info that 30 more tickets than 3 times the amount of children's were sold than adult)

then for equation 2:

3c + 5a = 2820

(this is because of the prices of the tickets and the total money raised)

Then, plug in the equation for c

Your equation should look like:

3 (3a + 30) + 5a = 2820

You get:

(9a + 90) + 5a = 2820

Then:

14a = 2730

So:

a = 195 adult tickets sold

Plug in a, to find c:

3 (195) + 30 = c

585 + 30 = c

c = 615 children tickets sold