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Mathematics
Titus Parks
3 February, 21:08
What is the zero for 2x2-7=4
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Geovanni Zuniga
3 February, 21:33
0
2x² - 7 = 4
+7 + 7
2x² = 11
2 2
x² = 5 1/2
x = √5 1/2
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Chessie
3 February, 22:30
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2x^2-7=4
subtract 4 from both sdies
2x^2-11=0
therefor
2x^2=11
divide by 2
x^2=5.5
square root both sdies
x=-2.345 or 2.345
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