You have three pieces of paper in an envelope. One piece of paper has the number 1 written on it, another has the number 2 written on it, the other has the number 3 written on it. You draw and replace a piece of a paper three times. What is the probability that it's in this order (1,2,3) or this order (2,2,2) ?

Question

Mathematics

Sexton

20 April, 10:53

You have three pieces of paper in an envelope. One piece of paper has the number 1 written on it, another has the number 2 written on it, the other has the number 3 written on it. You draw and replace a piece of a paper three times. What is the probability that it's in this order (1,2,3) or this order (2,2,2) ?

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Answers (1)

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Rhett Maynard · Answer 1

See below in bold.

Step-by-step explanation:

Prob (1 is first drawn) = 1/3

Prob (2 is second) = 1/2

Prob (3 is 3rd) = 1/3

So probability of 1,2,3 is (1/3) ^3 = 1/27.

(2,2,2) is the same probabiilty 1/27.