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The average mark of candidate in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are 148, 102,152. What is the average of the extracted scores t hat are extreme values (outliers) ?

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  1. Today, 12:42
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    Step-by-step explanation:

    Given that : The average marks of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are; 148, 102 and 152.

    The objective here is to determine the average of the extracted scores that are the extreme values (outliers)

    NOW:

    The average marks of candidates in an aptitude test was 128.5

    i. e the Mean = 128.5

    Standard Deviation = 8.2

    outlier will be outsides;

    then the range will be Mean ± 3 * SD

    = 128.5 ± 8.2 * 3

    = 128.5 ± 24.6

    Range is (103.9, 153.1)

    102 is outside this range

    Hence, the average of the extracted scores that are extreme values (outliers) will be 102 only
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