How would you complete the square on the left side of this equation? x^2-6x=15 A. Add 6 to both sides of the equation. B. Subtract 6 from both sides of the equation. C. Add 9 to both sides of the equation. D. Subtract 9 from both sides of the equation.

Question

Mathematics

Cutie

24 July, 09:47

How would you complete the square on the left side of this equation? x^2-6x=15 A. Add 6 to both sides of the equation. B. Subtract 6 from both sides of the equation. C. Add 9 to both sides of the equation. D. Subtract 9 from both sides of the equation.

+3

Answers (2)

Know the Answer?

Melany · Answer 1

C

Step-by-step explanation:

x²-6x+9=15+9

/[ (x-3) ²=24/]

x-3±2√6

x=3±2√6

Pierce Maxwell · Answer 2

The answer to your question is letter C

Step-by-step explanation:

x² - 6x = 15

Process

1. - Divide the middle term by 2

-6 / 2 = - 3

2. - Add the result to both sides

x² - 6x + (-3) ² = 15 + (-3) ²

3. - Simplify

x² - 6x + 9 = 15 + 9

4. - Conclusion

Add 9 to both sides of the equation