A triangle with one side twice the length of the shortest side and the third side is 17 feet more than the length of the shortest side. Find the dimensions of the perimeter is 133 ft

29 ft, 46 ft, 58 ft

Step-by-step explanation:

Let the length of the shortest side is equal to x ft

Now given the length of the second side is twice the length of the shortest side which means 2x ft

Also given that the length of the third side is 17 ft more than the length of of the shortest side which means 17+x ft.

Given perimeter=133 ft

Perimeter=sum of the lengths of the sides.

133=x+2x+17+x

4x=116

x=29

the dimensions are 29 58 46.