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21 May, 13:39

A square that has 28 cm long edges is centered on the x-axis in a region where there exists a uniform electric field given by = (1.2 kN/C). What is the electric flux of this electric field through the surface of a square if the normal to the surface is in the + x direction?

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  1. 21 May, 17:00
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    Step-by-step explanation:

    From ΦE = ∫s E * dA Given E = 1.2 kN/C = 1200N/C L = 28cm = 0.28m A = Area = (0.28) ^2 = 0.0784m^2 electric flux = EA = 1200N/C x 0.0784m^2

    = 94.08Nm2/C
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