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20 May, 17:12

Find the number of 3-digit numbers formed using the digits 1 to 9, without repetition, such the numbers either have all digits less than 5 or all digits greater than 4.

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  1. 20 May, 19:31
    0
    84

    Step-by-step explanation:

    Given,

    The possible digits are 9 (i. e. 1, 2, 3, 4, 5, 6, 7, 8, 9)

    Digits less than 5 = 4 (i. e. 1, 2, 3, 4)

    Digits greater than 4 = 5 (i. e. 5, 6, 7, 8, 9)

    Here, we need to make 3 digit number from these digits without repeating,

    If digits are less than 5,

    Then the possible ways = 4 * 3 * 2

    = 24

    If digits are greater than 4,

    Then the possible ways = 5 * 4 * 3

    = 60

    Hence, the total ways of choosing three digits number without repeating if all digits are less than 5 or all digits are greater than 4

    = 24 + 60

    = 84
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