Ask Question
13 September, 07:20

3 consecutive integers are such that the when the smallest is multiplied by 3 is 18 more than the largest

+4
Answers (2)
  1. 13 September, 08:42
    0
    Answer: 10, 11, 12

    Step-by-step explanation:

    Let the integers be : x, x + 1 and x + 2

    the smallest multiplied by 3 implies 3x

    From the first statement

    3x = 18 + (x+2)

    3x = 18 + x + 2

    3x - x = 18 + 2

    2x = 20

    x = 10

    Therefore : the numbers are : 10, 10 + 1 and 10 + 2

    the numbers are : 10, 11, 12
  2. 13 September, 09:51
    0
    10,11,12

    Step-by-step explanation:

    3 consecutive integers ... x and x + 1 and x + 2

    3x = x + 2 + 18

    3x = x + 20

    3x - x = 20

    2x = 20

    x = 20/2

    x = 10

    x + 1 = 10 + 1 = 11

    x + 2 = 10 + 2 = 12

    ur numbers are 10, 11, and 12
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “3 consecutive integers are such that the when the smallest is multiplied by 3 is 18 more than the largest ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers