Ask Question
13 February, 09:11

The population of anywhere USA was estimated to be 568,600 in 2002, with an expected increase of 4.8% per year. At the rate of increase given what is the expected population in 2003 round your answer to nearest integer

+5
Answers (1)
  1. 13 February, 11:15
    0
    595892

    Step-by-step explanation:

    Population in 2002 was estimated to be 568,600.

    Expected increase of 4.8% per year.

    That Is 4.8% / 100%x 568,600

    0.48 x 568600

    27292.8

    27293

    In 2003 the population at an increased rate of 4.8% will be

    27293 + 568600

    = 595892
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The population of anywhere USA was estimated to be 568,600 in 2002, with an expected increase of 4.8% per year. At the rate of increase ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers