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20 April, 02:07

5d + 2 (2-d) = 3 (1+d) + 1 Solve for d

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  1. 20 April, 02:32
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    infinite solutions

    Step-by-step explanation:

    5d + 2 (2-d) = 3 (1+d) + 1

    Distribute

    5d + 4-2d = 3 + 3d + 1

    Combine like terms

    3d + 4 = 3d+4

    Subtract 3d from each side

    3d-3d + 4 = 3d-3d + 4

    4=4

    Since this is always true

    d has infinite solutions
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