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Mathematics
Leah Cannon
30 July, 17:42
If x = - 2 and x^2+y^2+3xy = -5, then find y
+3
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1
)
K
Kassidy Murphy
30 July, 19:05
0
y = 3
Step-by-step explanation:
Given:
x²+y²+3xy = -5 and x = - 2
Substituting x=-2 into the equation:
(-2) ² + y² + 3y (-2) = - 5
4 + y² - 6y = - 5
y² - 6y + 4 + 5 = 0
y² - 6y + 9 = 0 (solve by factorization)
(y-3) (y-3) = 0
y = 3
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