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30 July, 17:42

If x = - 2 and x^2+y^2+3xy = -5, then find y

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Answers (1)
  1. K
    30 July, 19:05
    0
    y = 3

    Step-by-step explanation:

    Given:

    x²+y²+3xy = -5 and x = - 2

    Substituting x=-2 into the equation:

    (-2) ² + y² + 3y (-2) = - 5

    4 + y² - 6y = - 5

    y² - 6y + 4 + 5 = 0

    y² - 6y + 9 = 0 (solve by factorization)

    (y-3) (y-3) = 0

    y = 3
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