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3 April, 00:30

A ball is thrown straight up with a speed of 12 meters per second near the surface of Earth. What is the maximum height reached by the ball?

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Answers (2)
  1. 3 April, 01:54
    0
    maximum height = 7.347m

    Step-by-step explanation:

    maximum height = (U²sin²θ) / 2g

    where θ = 90° as the ball is thrown straight up.

    sin90°=1, so our formula reduces to;

    H = U²/2g

    U=12m/s, g=9.8m/s²

    H = 12² / (2*9.8)

    H=7.347m
  2. 3 April, 02:02
    0
    Answer:H=7.339m

    Step-by-step explanation:

    The formula to find maximum height is:

    H = v^2 / (2 * g)

    V means speed=12 m/s

    g means acceleration due gravity (constant) = 9.81m/s^2

    Apply the formula

    H = (12^2) / (2*9.81)

    H=144/19.62

    H=7.339m
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