X^2-5x=14 solve for x

x = - 2, x = 7

Step-by-step explanation:

Given

x² - 5x = 14 (subtract 14 from both sides)

x² - 5x - 14 = 0 ← in standard form

Consider the factors of the constant term ( - 14) which sum to give the coefficient of the x - term ( - 5)

The factors are - 7 and + 2, since

- 7 * 2 = - 14 and - 7 + 2 = - 5, thus

(x - 7) (x + 2) = 0

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 7 = 0 ⇒ x = 7

x=7, - 2.

Step-by-step explanation:

x^2-5x=14

x^2-5x-14=0

factor out the trinomial,

(x-7) (x+2) = 0

zero property,

x-7=0, x+2=0,

x=0+7=7,

x=0-2=-2