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Kasen Sims
13 March, 14:02
X^2-5x=14 solve for x
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Malakai Calderon
13 March, 14:58
0
x = - 2, x = 7
Step-by-step explanation:
Given
x² - 5x = 14 (subtract 14 from both sides)
x² - 5x - 14 = 0 ← in standard form
Consider the factors of the constant term ( - 14) which sum to give the coefficient of the x - term ( - 5)
The factors are - 7 and + 2, since
- 7 * 2 = - 14 and - 7 + 2 = - 5, thus
(x - 7) (x + 2) = 0
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
x - 7 = 0 ⇒ x = 7
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Davenport
13 March, 15:13
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x=7, - 2.
Step-by-step explanation:
x^2-5x=14
x^2-5x-14=0
factor out the trinomial,
(x-7) (x+2) = 0
zero property,
x-7=0, x+2=0,
x=0+7=7,
x=0-2=-2
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