Ask Question
23 October, 06:00

C (n) = - 6 / left (-/dfrac{1}{3}/right) ^{n - 1}c (n) = -6 ( - 3 1 ) n-1 c, left parenthesis, n, right parenthesis, equals, minus, 6, left parenthesis, minus, start fraction, 1, divided by, 3, end fraction, right parenthesis, start superscript, n, minus, 1, end superscript What is the 2^/text{nd}2 nd 2, start superscript, start text, n, d, end text, end superscript term in the sequence?

+1
Answers (1)
  1. 23 October, 06:24
    0
    Answer: The second term of the sequence is 2

    Step-by-step explanation:

    Given the function c (n) = - 6 (-1/3) ^n-1

    To get the second term of the sequence, we will substitute n = 2 into the given function to have;

    c (2) = - 6 (-1/3) ^2-1

    c (2) = - 6 (-1/3) ^2-1

    c (2) = - 6 (-1/3) ^1

    C (2) = - 6 (-1/3)

    Since - * - a = +

    C (2) = + 6/3

    C (2) = 2

    Therefore the second term of the sequence is 2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “C (n) = - 6 / left (-/dfrac{1}{3}/right) ^{n - 1}c (n) = -6 ( - 3 1 ) n-1 c, left parenthesis, n, right parenthesis, equals, minus, 6, left ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers