A bag contains only 3 blue disks, 3 green disks, and 4 orange disks. If 3 disks are selected at random from the bag, what is the probability that 1 of the disks will be green and 2 of the disks will be orangeA) 1/30

B) 1/20

C) 3/40

D) 1/10

E) 3/20

E = 3/20

Step-by-step explanation:

Number of blue disk = 3

Number of green disk = 3

Number of orange disk = 4

Total number of disk = 3+3+34

= 10

Let B represent blue disk

Let G represent green disk

Let O represent orange disk

If three disk are selected at random, the possible outcome of one green disk and two orange disks are

OOG, OGO, GOO

Pr (OOG) = Pr (O1) * Pr (O2) * Pr (G3)

= 4/10 * 3/9 * 3/8

= 36/720

= 1/20

Pr (OGO) = Pr (O1) * Pr (G2) * Pr (O3)

= 4/10 * 3/9 * 3/8

= 36/720

= 1/20

Pr (GOOG) = Pr (G1) * Pr (O2) * Pr (O3)

= 4/10 * 4/9 * 3/8

= 36/720

= 1/20

Pr (total) = Pr (OOG) + Pr (OGO) + Pr (GOO)

= 1/20 + 1/20 + 1/20

= 3/20