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21 January, 22:53

A tank, shaped like a cone has height 11 meter and base radius 4 meter. It is placed so that the circular part is upward. It is full of water, and we have to pump it all out by a pipe that is always leveled at the surface of the water. Assume that a cubic meter of water weighs 10 000 N

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  1. 21 January, 23:18
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    The tank is a cone, so the radius of the cross section increases linearly with h

    At y=0, r=4 and at y=11, r=0

    So

    r (y) = 4/11 (11-y)

    A (y) = π[4 (11-y) 11]^2

    Integral will be:

    11∫0 (1000) (9.8) (4πy^2) (25) (11-y) dy
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