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16 December, 03:50

Jess had three more nickels than dimes for a total of $1.50 how many of each coin did he

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  1. 16 December, 05:34
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    n = d + 3

    5n + 10d = 150 cents

    Substitute to solve for "d":

    5 (d+3) + 10d = 150

    15d + 15 = 150

    15d = 135

    d = 9 dimes

    n = d+3 = 9+3 = 12 nickels

    So 12 nickels!
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