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23 October, 14:40

Solve system of equation y=x^2+3x+1, y=-x-3

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  1. 23 October, 16:06
    0
    x = - 2

    y = - 1

    Step-by-step explanation:

    y = x² + 3x + 1 y = - x - 3

    Set the equations equal to each other:

    x² + 3x + 1 = - x - 3

    Move all terms to one side:

    x² + 3x + x + 1 + 3 = 0

    x² + 4x + 4 = 0

    factor:

    (x + 2) ² = 0

    take square root of both sidesL

    x + 2 = 0

    subtract 2 from both sides:

    x = - 2

    Plug - 2 in for x in either of the equations:

    (-1) ²+3 (-1) + 1 = y

    y = - 1
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