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7 January, 19:44

Consider the rate law below. R=k (NO2) ^2 what happens to the rate if the concentration is tripled?

The rate increases by a factor of 9.

The rate decreases by a factor of 6.

The rate triples.

The rate doubles.

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Answers (1)
  1. 7 January, 22:21
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    For this case we have the following equation:

    R = k (NO2) ^ 2

    if the concentration is tripled, we must rewrite the equation.

    We have then:

    R ' = k (3 * NO2) ^ 2

    R ' = 9 * k (NO2) ^ 2

    Rewriting:

    R ' = 9 * R

    Answer:

    The rate increases by a factor of 9.
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