The ordered array below represents the number of cargo manifests approved by customs inspectors of the Port of New York in a sample of 35 days: 16, 17, 18, 18, 19, 20, 20, 21, 21, 21, 22, 22, 22, 22, 23, 23, 23, 23, 24, 24, 24, 25, 25, 26, 26, 26, 27, 28, 28, 29, 29, 31, 31, 32, 32 Note: For this sample, the sum of the values is 838, and the sum of the squared differences between each value and the mean is 619.89. Referring to Scenario 3-4, the third quartile of the customs data is

Question

Mathematics

Ayanna Johnson

13 October, 04:11

The ordered array below represents the number of cargo manifests approved by customs inspectors of the Port of New York in a sample of 35 days: 16, 17, 18, 18, 19, 20, 20, 21, 21, 21, 22, 22, 22, 22, 23, 23, 23, 23, 24, 24, 24, 25, 25, 26, 26, 26, 27, 28, 28, 29, 29, 31, 31, 32, 32 Note: For this sample, the sum of the values is 838, and the sum of the squared differences between each value and the mean is 619.89. Referring to Scenario 3-4, the third quartile of the customs data is

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Answers (1)

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Helena Miranda · Answer 1

the third quartile of the customs data is 27

Step-by-step explanation:

For the third quartile, we should first find upper half of the data and then the median of the upper half.

lower half: 16, 17, 18, 18, 19, 20, 20, 21, 21, 21, 22, 22, 22, 22, 23, 23, 23,

median: 23

upper half: 24, 24, 24, 25, 25, 26, 26, 26, 27, 28, 28, 29, 29, 31, 31, 32, 32

Middle value (median) of the upper half is: 27 since 8 of the values are lower than 27 and 8 of the values are higher than 27.