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2 December, 20:59

Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero. Steps Reasons 1. a over b plus c over d Given 2. Multiply to get a common denominator 3. ad plus cb all over bd Simplify Fill in the missing step in the proof. ac over bd ad over b plus cb over d a plus c all over b plus d ad over bd plus cb over bd

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  1. 2 December, 21:37
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    ad+bc/bd is a rational number.

    Step-by-step explanation:

    We know that the rational numbers are those numbers which can be written in p/q form. and q is not equal to zero

    Lets say that a/b and c/d are two rational numbers and both the denominators b and d can not be zero.

    We have given:

    a/b + c/d

    Now multiply the given term to get a common denominator

    a/b + c/d = ad/bd + cb/db

    Now if we simplify the given term we get:

    a/b + c/d = ad/bd + cb/db

    Take the L. C. M of the denominator.

    ad/bd + cb/db

    Notice that the denominators are same. Thus the term we get after taking L. C. M we get

    =ad+cb/bd

    =a/b + c/d = ad/bd + cb/db = ad+bc/bd

    Since b and d are not equal to zero, bd is also not equal to zero.

    And a, b, c, d are integers then bd, ad, bc, ad + bc are also integers.

    Thus the fraction ad+bc/bd is a rational number.
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