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16 August, 16:39

Find dy/dx if. y = inverse of cos x

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  1. 16 August, 17:23
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    dy/dx = - 1 / √ (1 - x^2).

    Step-by-step explanation:

    y = arccos x.

    So x = cos y

    dx / dy = - sin y

    dy / dx = - 1 / sin y

    But sin y = √ (1 - cos^2 y)

    But cos y = x, so cos^2y = x^2

    Therefore

    dy/dx = - 1 / √ (1 - x^2).
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