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31 October, 16:38

Mary has a collection of nickels and quarters for a total of $4.90. If she has 42 coins in total, how many of each kind are there?

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  1. 31 October, 17:20
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    14 quarters and 28 nickels

    Step-by-step explanation:

    System of Equations where x = number of quarters and y = number of nickels

    (1) equation with value of each coin

    0.25 (x) + 0.05 (y) = 4.90

    (2) total number of coins

    x + y = 42

    Solve system of equations using either substitution or elimination

    (elimination multiplying equation 2 by - 0.5)

    .25 (x) + 0.05 (y) = 4.90

    -0.05 (x) - 0.05 (y) = 42 * (-0.05)

    (3) Resulting equation

    .20 (x) = 2.8

    x = 14

    plug x into equation 2

    14 + y = 42

    y = 28

    There are 14 quarters and 28 nickels in Mary's collection.
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