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11 April, 12:04

Leila's company makes solid metal balls for various industrial uses. A customer wants lead balls that have a diameter of 6 in. If Leila must make 80 of these balls, how much lead will she need?

Use 3.14 for Pi, and do not round your answer.

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  1. 11 April, 12:53
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    9043.2 in^3 of lead

    Step-by-step explanation:

    the formula is (4/3) (3.14) r^3

    so,

    (4/3) (3.14) (3^3) * 80

    9043.2
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