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20 July, 23:06

If x+y+z=13 what is the value of (x-1) + (y+1) + (z-1)

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  1. 21 July, 00:37
    0
    12

    Step-by-step explanation:

    (x-1) + (y+1) + (z-1)

    = x - 1 + y + 1 + z - 1

    = x + y + z - 1

    = (x + y + z) - 1

    given that x+y+z = 13, substitute this value into the equation aove

    (x + y + z) - 1

    = 13 - 1

    = 12
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