Ask Question
4 April, 15:44

A diesel train left Washington and traveled

toward Johannesburg at an average speed of

52 mph. A cattle train left two hours later

and traveled in the same direction but with

an average speed of 60 mph. Find the

number of hours the diesel train traveled

before the cattle train caught up.

+4
Answers (1)
  1. 4 April, 19:14
    0
    The number of hours the diesel train traveled before the cattle train caught up is 15 hours

    Solution:

    Let t = travel time of the diesel train

    Then (t - 2) is the travel time of the cattle train (Left 2 hrs later)

    Average speed of diesel train = 52 mph

    Average speed of cattle train = 60 mph

    To find: number of hours the diesel train traveled before the cattle train caught up

    Distance = speed x time

    Distance traveled by diesel train:

    Distance = 52 x t = 52t

    Distance traveled by cattle train:

    Distance = 60 x (t - 2) = 60t - 120

    When the cattle train catches the diesel, they will have traveled the

    same distance

    Distance traveled by diesel train = Distance traveled by cattle train

    52t = 60t - 120

    60t - 52t = 120

    8t = 120

    t = 15

    Thus the number of hours the diesel train traveled before the cattle train caught up is 15 hours
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A diesel train left Washington and traveled toward Johannesburg at an average speed of 52 mph. A cattle train left two hours later and ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers