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18 November, 23:45

If f (x) = x^2+9x and g (x) = 1/x, find f (g (-1)).

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  1. 19 November, 03:08
    0
    x=3

    Step-by-step explanation:

    x^2-9

    bcos g (-1) = -1

    f (g) = x^2+9 (-1) = 0

    x^2-9=0

    x^2=9

    x=√9

    x=3
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