Quadratic formula for 2x^+5x-7

x = - (7/2) ^ (1/6) or x = (7/2) ^ (1/6) or x = - (-1) ^ (1/3) (7/2) ^ (1/6) or x = (-1) ^ (1/3) (7/2) ^ (1/6) or x = - (-1) ^ (2/3) (7/2) ^ (1/6) or x = (-1) ^ (2/3) (7/2) ^ (1/6)

Step-by-step explanation:

Solve for x:

2 x^6 - 7 = 0

Add 7 to both sides:

2 x^6 = 7

Divide both sides by 2:

x^6 = 7/2

Taking 6^th roots gives (7/2) ^ (1/6) times the 6^th roots of unity:

Answer: x = - (7/2) ^ (1/6) or x = (7/2) ^ (1/6) or x = - (-1) ^ (1/3) (7/2) ^ (1/6) or x = (-1) ^ (1/3) (7/2) ^ (1/6) or x = - (-1) ^ (2/3) (7/2) ^ (1/6) or x = (-1) ^ (2/3) (7/2) ^ (1/6)