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6 May, 16:14

The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with acceleration of - 5.65 m/s2 for 4.00 s, making straight skid marks 62.9 m long, all the way to the tree. With what speed (in m/s) does the car then strike the tree?

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  1. 6 May, 18:01
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    Answer: the speed with which the car strikes the tree is 27.025 m/s

    Step-by-step explanation:

    We would apply Newton's equation of motion. It is expressed as

    S = ut + 1/2at²

    Where

    S represents the distance covered by the car

    u represents the initial velocity of the car (the speed with which the car strikes the tree)

    t represents the time taken to cover the distance

    a represents the deceleration of the car.

    From the information given,

    S = 62.9 meters

    a = - 5.65 m/s2

    t = 4 seconds

    Therefore

    62.9 = u * 4 + 1/2 * - 5.65 * 4²

    62.9 = 4u - 45.2

    4u = 62.9 + 45.2

    4u = 108.1

    u = 108.1/4 = 27.025 m/s
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