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2 December, 10:35

What is the solution to the system of equations?

(3x+2y = 39

(5x-y=13

O (4,7)

O (7,4)

O (12,5)

(5, 12)

+2
Answers (2)
  1. 2 December, 12:39
    0
    X = 5

    Y = 12

    Step-by-step explanation:

    3x + 2y = 39 - > (1)

    5x - y = 13 - > (2)

    Multiply (2) with 2

    10x - 2y = 26 - > (b)

    (1) + (b)

    This will eliminate the y factor, leaving:

    13x = 65

    Therefore, x = 65/14

    X = 5. Put this value of 5 in equation 1, which gives;

    15 + 2y = 39

    2y = 39-25

    2y = 24

    Y = 12
  2. 2 December, 13:32
    0
    x=5

    y = 12

    Step-by-step explanation:

    3x + 2y = 39

    2y = 39 - 3x

    y = (39 - 3x) / 2

    5x - y = 13

    5x - ((39 - 3x) / 2) = 13

    5x - 39/2 + 3/2x = 13

    5x + 3/2x = 13 + 39/2

    13/2x = 65/2

    x = 65/2 * 2/13

    x = 65/13

    x = 5

    y = (39 - 3x) / 2

    y = (39 - 3*5) / 2

    y = (39 - 15) / 2

    y = 24/2

    y = 12
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