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9 June, 15:03

What is the first step in writing f (x) = 6x2 + 5 - 42x in vertex form?

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  1. 9 June, 16:19
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    Back to seeks out of the first two times
  2. 9 June, 18:24
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    The first step in writing f (x) = 6x^2 + 5 - 42x in vertex form is to put it into proper quadratic form and then finding the axis of symmetry. Proper quadratic form is ax^2 + bx + c. The formula to find the axis of symmetry is - b over 2a.
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