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16 March, 03:51

Suppose that you are running a concession stand when a person gives you $18 and asks for six soft drinks and as many hot dogs as the remaining money will buy. If soft drinks are $1.00 and hot dogs are $1.75, what is the maximum number of hot dogs the person can buy?

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Answers (2)
  1. 16 March, 04:05
    0
    Answer: 6 hot dogs

    Step-by-step explanation:

    The person gave you $18, first, we will charge the six soft drinks, that each one costs $1

    So the six drinks cost $6

    the remaining money is $18 - $6 = $12

    Now, with the $12 the customer wants to buy hot dogs, that each cost $1.75

    The number of hot dogs can be obtained by dividing the total money by the price of a hot dog:

    N = $12/1.75 = 6.8

    But you can not buy an 0.8 of a hot dog, so we must round to the whole number:

    N = 6

    So the maximum number of hot dogs that the money can buy is 6
  2. 16 March, 07:04
    0
    the max number of hot dogs he can buy is 6 with change left

    Step-by-step explanation:

    18.00 - 6.00 = 12.00 / 1.75 = 6.8
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