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2 September, 19:33

There is a population of 1,000,000 bacteria in a colony. If the number of bacteria doubles every 270 hours, what will the population be in 810 hours from now?

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  1. 2 September, 20:41
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    Answer:8000000 bacteria

    Step-by-step explanation:

    We would apply the formula,

    y = ab^t

    Where

    A represents the initial amount of bacteria.

    t represents the doubling time.

    From the information given

    A = 1000000

    t = 270 hours

    Since after 270 hours, the population doubles, then

    y = 2 * 1000000 = 2000000

    Therefore

    2000000 = 1000000 * b^270

    2 = b^270

    Raising both sides of the equation by 1/270, it becomes

    2^ (1/270) = b

    The equation becomes

    y = 1000000 * 2^ (1/270) * t

    y = 1000000 * 2^ (t/270)

    Therefore, the population in 810 hours hours time would be

    y = 1000000 * 2^ (810/270)

    y = 1000000 * 2^3

    y = 8000000 bacteria
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