Mathematics

Ronan Morales

19 July, 14:20

Which quadratic function has one real solution?

0 = 2 (x + 7) (x - 5)

0 = (x - 3) (x - 3) The quadratic function f (x) = - x2 - 6x - 8 is graphed.

What are the solutions of the quadratic equation 0 = - x2 - 6x - 8?

2 and - 4

-2 and 4

-2 and - 4

2 and 4

0 = 2.4 (x - 2) (x + 2)

0 = (x - 2) (x - 1)

+4

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