Solve the following system of equations algebraically and check.

y=x^2+3x+4

y-x=7

Y=x^2+3x+4

y-x=7

x^2+3x+4-x=7

x^2+2x+4=7

(factor) x^2+2x-3=0

(x+3) (x-1) = 0

X = - 3 and X=1

(Plug x in for y)

Y = 1^2+3 (1) + 4

Y=8

(Check your answer on the second equation)

8-1=7

7=7 (Which is the solution)