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29 March, 18:24

a bag has more green balls than blue balls and there is at least one blue ball. let b represent the number of blue balls and let g represent the number of green balls.

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  1. 29 March, 22:02
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    2) 2 b < b + g

    Step-by-step explanation:

    Here, the given question is incomplete.

    A bag has more green balls than blue balls, and there is at least one blue ball.

    Let b represent the number of blue balls and let g represent the number of green balls.

    Let's compare the expressions 2 b and b + g. Choose the correct statement?

    1. 2 b > b + g

    2. 2 b < b + g

    3. 2 b = b + g

    4. There is not enough information to tell.

    Now, here given:

    b: the number of blue balls

    g: the number of green balls

    Also, the number of green balls is greater than blue balls.

    ⇒ g > b

    Also, b ≥ 1 as the blue ball is one or more in number.

    Now, as b is at least one.

    So, g being more than b, we get: b ≥ 2

    So, from given equations, we get:

    g > b

    b ≥ 2

    Adding the respective sides, we get:

    g + b ≥ 2 + b

    or, 2 b < b + g
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