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31 July, 04:12

How to solve y=2x+5 and y=3x-1 by a system of linear equations by substitution

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Answers (2)
  1. 31 July, 06:18
    0
    2x + 5 = 3x - 1

    -2x - 2x

    5 = 1x - 1

    +1 + 1

    6 = 1x

    6/1 = 6

    X = 6
  2. 31 July, 07:26
    0
    x = 6, y = 17

    Step-by-step explanation:

    These equations are both equal to y.

    Substitute 3x - 1 in the y value of the first equation.

    3x - 1 = 2x + 5

    Subtract 2x.

    x - 1 = 5

    Add 1 to both sides

    x = 6

    Then substitute this x value into the first equation.

    y = 2x + 5

    y = 2 (6) + 5 = 12 + 5 = 17
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