Give the first five terms of the sequence

an=2n2+2

The answer to your question is 3, 9, 19, 33, 51

Step-by-step explanation:

Sequence an = 2n² + 1

1st term a₁ = 2 (1) ² + 1 = 2 (1) + 1 = 2 + 1 = 3

2nd term a₂ = 2 (2) ² + 1 = 2 (2) ² + 1 = 2 (4) + 1 = 8 + 1 = 9

3rd term a₃ = 2 (3) ² + 1 = 2 (3) ² + 1 = 2 (9) + 1 = 18 + 1 = 19

4rd term a₄ = 2 (4) ² + 1 = 2 (4) ² + 1 = 2 (16) + 1 = 32 + 1 = 33

5th term a₅ = 2 (5) ² + 1 = 2 (5) ² + 1 = 2 (25) + 1 = 50 + 1 = 51