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14 April, 16:57

A right triangle has the side legnths 4 units, 5 units, and x units. It is unknown if the missing length is the longest or shortest side.

Rounded to the nearest tenth, what is the difference between the possible values of x?

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  1. 14 April, 18:16
    0
    For longest x = 6.4

    For shortest x = 3

    Step-by-step explanation:

    Given a right angle triangle with lengths 4 units and 5 units and x units.

    x can be gotten using Pythagoras theorem.

    If x Is the longest side, then

    x^2 = 5^2 + 4^2

    = 5x5 + 4x4

    = 25 + 16

    x^2 = 41

    x = squared root of 41

    x = 6.4

    If x is the shortest side,

    x^2 = 5^2 - 4^2

    = 5x5 - 4x4

    = 25 - 16

    x^2 = 9

    x = squared root of 9

    x = 3
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