3 consecutive odd integers that the sum of the smallest and 4 times the largest is 61

Let the smallest number be = x

So the next big number = x+2

And the largest number = x+4

x + 4 (x+4) = 61

x + 4x + 16 = 61

5x + 16 = 61

5x = 61-16 = 45

So x = 45/5 = 9

Therefore, the numbers are 9, 11 and 13. Answer.

gsm