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31 October, 12:02

A can of StarKist tuna has a volume LaTeX: 18/pi/:cm^318 π c m 3 and a height of 2 cm. Find the area of the StarKist label below the wraps around the entire can and does not overlap. Write your answers in terms of LaTeX: / piπ.

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  1. 31 October, 14:55
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    Area of the StarKist label around the can in terms of π = 12π cm²

    Step-by-step explanation:

    Given;

    the volume of a can of StarKist tuna, V = 18 π cm³

    height of the can of StarKist tuna, h = 2 cm

    To determine the area of the StarKist label that wraps around the entire can and does not overlap, we assume the can to have a shape of a cylinder.

    Volume of the can = πr²h

    where;

    r is radius of the can

    h is height of the can

    πr² x 2 = 18 π

    2r² = 18

    r² = 18/2

    r² = 9

    r = 3

    Area around the can = curved surface area of the can (cylinder)

    Curved surface area of the can = 2πr * h = 2πrh

    Curved surface area of the can = 2πrh = 2π x 3 x 2 = 12π cm²

    Area of the StarKist label around the can in terms of π = 12π cm²
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