Determine whether the given function has a maximum or a minimum value. Then, find the maximum or minimum value of the function. f (x) = 1x^2-8x+6

The standard form equation of the parabola is y = ax^2 + bx + c. To figure out whether your function has a maximum or a minimum value, you must look at "a" in the standard form equation (other equation forms work as well). Since your "a" is positive, the parabola of the given function is open upwards. That been said, the function has a minimum value. You can use the following equation - b/2a to find the x-coordinate of the parabola's vertex. After finding the x-coordinate, simply plug the value of - b/2a into the equation f (x) = 1x^2 - 8x + 6 to find the y-coordinate of the vertex. The answer is (4, - 10).

Answer: maximum value is 2