Determine if the expressions are equivalent: 7 + 7x; 7 x + 1/7

The given expressions 7 + 7x; 7 x + 1/7 are not equivalent or equal

to each other

Step-by-step explanation:

Let us firstly assume that 7 + 7x is equivalent (to 7 (x + 1/7) so that means

7 + 7x = 7 (x + 1/7)

7 + 7x = 7x + 7 (1/7)

7 + 7x = 7x + 1

7x + 7 = 7x + 1

Now, subtracting 7x from both sides, we get:

7x - 7x + 7 = 7x - 7x + 1

(7 - 7) x + 7 = (7 - 7) x + 1

(0) x + 7 = (0) x + 1 thus their occurs a false statement:

7 = 1 (we know, 7 >1)

Thus we can say that

7 + 7x is NOT equivalent to 7 (x + 1/7)