Given the equation (x - 13) ^ 2 + y ^ 2 = 64 identify the center and radius

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Mathematics

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6 May, 13:48

Given the equation (x - 13) ^ 2 + y ^ 2 = 64 identify the center and radius

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Answers (1)

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Lyric Hoover · Answer 1

radius is 8; center is at (13, 0).

Step-by-step explanation:

Compare the given (x - 13) ^ 2 + y ^ 2 = 64 to:

(x - h) ^2 + (y - k) ^2 = r^2. (h, k) represents the center

and r the radius.

Since 64 = r^2, r = the radius = 8 units = r

We also see that h = 13 and k = 0.

Thus, the center of the given circle is (13, 0).