An arrow is launched upward with a velocity of 320 feet per second from the top of a 45-foot building. What is the maximum height attained by the arrow?

Maximum height reached is 804.88 m

Step-by-step explanation:

At maximum height velocity is zero

We have equation of motion v² = u² + 2as

Initial velocity, u = 320 ft/s = 97.536 m/s

Final velocity, v = 0 m/s

Acceleration, a = - 9.81 m/s²

Substituting

v² = u² + 2as

0² = 97.536² + 2 x - 9.81 x s

s = 484.88 m

So the arrow further a height of 484.88 m

Total height = 320 + 484.88 = 804.88 m

Maximum height reached is 804.88 m