100
10, UUS
11. A ball is thrown upward at a velocity of 15 meters per second from a height that is 20
meters above the ground. The height h (in meters) of the ball at time t in seconds) after it
is thrown can be found by h (t) = - 5t^2 + 15t + 20. Find the time when the ball is again 20
meters above the ground.
A
1 second
(B
2 seconds
C
3 seconds
D
4 seconds
Answers (1)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “100 10, UUS 11. A ball is thrown upward at a velocity of 15 meters per second from a height that is 20 meters above the ground. The height ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers
You Might be Interested in
I am once in year, twice aweek. who go am I?
Answers (2)
The admission price is $10 and $ 5.50 is for the theater rental
Answers (1)
You are playing basketball with your friends. The height (in feet) of the ball above the ground t seconds after a shot is released from your hand is modeled by the function f (x) = -16^2 + 32t + 5.2
Answers (1)
24.50x + 22.00 = 18.25x + 47
Answers (2)
For the functions f (x) = 4x^2 and g (x) = -7x^2, find (f-g) (x) and (f-g) (0)
Answers (1)
New Questions in Mathematics
7/8=?/48 A. 42 B. 13 C. 1 D. 6
Answers (1)
The quotient of 2 times a number and 8 a. 16x b. 8x/2 c. 2x/8 d. x/16
Answers (1)
Solve for x. 5*-6=4*+8
Answers (2)
LaMia buys 133 stickers. The stickers come in packs of 19. How many packs does LaMia buy?
Answers (1)
To which sets of numbers does pi belong? Select each correct answer. A - integers B - real numbers C - rational numbers D - irrational numbers
Answers (2)