100
10, UUS
11. A ball is thrown upward at a velocity of 15 meters per second from a height that is 20
meters above the ground. The height h (in meters) of the ball at time t in seconds) after it
is thrown can be found by h (t) = - 5t^2 + 15t + 20. Find the time when the ball is again 20
meters above the ground.
A
1 second
(B
2 seconds
C
3 seconds
D
4 seconds
Answers (1)
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