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29 January, 21:56

Which equation is represented by the graph below?

On a coordinate plane, a curve approaches y = negative 4 in quadrant 3 and then increases exponentially in quadrant 1. It crosses the y-axis at (0, negative 3).

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  1. 30 January, 01:47
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    y = e^x - 4

    Step-by-step explanation:

    The missing options are

    y = ln x - 3

    y = ln x - 4

    y = e^x - 3

    y = e^x - 4

    The function is defined in quadrant 3 and increases exponentially, then it is not a logarithm.

    f (x) crosses the y-axis at (0, - 3). Replacing x = 0 the last option, we get:

    y = e^0 - 4 = 1 - 4 = - 3
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